关于如何接受异步ajax请求返回前台的数据

1、第一种方式通过bean,后台需封装成json数据格式,前台paseJSON();

public void checkCode() {

ResponseMessage rm = new ResponseMessage(true,null);

String hql = “from TblWrPeople t where t.wrPeopleCode='”+code+”‘ and t.delFlag='”+Constants.DELFLAGA+”‘”;

List<TblWrPeople> tblWrPeopleList = (List<TblWrPeople>)this.workResService.find(hql);

if (tblWrPeopleList != null && tblWrPeopleList.size() > 0) {

rm.setSuccess(false);

rm.setErrorMsg(“数据库中已存在该代号,请重新录入”);

this.responseAJAX(JSONObject.fromObject(rm).toString(), getResponse());

}

}

前台获取:

function checkCode() {

var code = $(“#wrPeopleCode”).val();

 $.post(‘workRes_checkCode.action’,{“code”:code},function(result){

 result = $.parseJSON(result);

 if (result.success == false){

alert(result.errorMsg);

$(“#wrPeopleCode”).val(”);

}

});

}

2、后台直接返回一个String类型的字符串,前台的话不再需要parseJSON,直接获取result即可;

未经允许不得转载:博客 » 关于如何接受异步ajax请求返回前台的数据

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